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Size of near and far planes of a box

4:02 PM, Thursday November 25th 2021

Hi, so I just want to confirm if I understood the concept right. I appreciate if anyone could help :)

  1. So, the face of a box that is further away from the viewer (further away in distance to the VP) should be smaller than the closer face, because stuff further away is just smaller

  2. However, due to viewing angle, an edge that is more turned towards the viewer is shorter than one that is more turned away from the viewer. (the concept described in the 250box challenge)

So to combine those two points: It can happen that the face that is closer to the VP is actually bigger than the face closer to the viewer... right? It's not a mistake, it's supposed to be that way sometimes, right?

I added a picture taken from the "how to draw a box video" with the grey face being smaller than it's parallel face... it's supposed to be like this, isn't it?

https://imgur.com/a/DNTolbn

It's quite difficult to put this into words, so I hoep it's not too confusing. Thanks for your help!

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2 users agree
10:43 PM, Thursday November 25th 2021

I think the problem is thinking in terms of "bigger". You will see more of the area of the furthest face ( as a percentage of looking at the same face of the box straight on ) as it is less turned away from you than the near one but it will be smaller in dimensions and area on the paper.

Helps?

3:41 PM, Tuesday November 30th 2021

Sorry for the really late reply!

It makes a lot of sense to think about it by comparing a face to its 100% straight-on face. I'll try to think like this while drawing my boxes and see if my confusion disappears :)

Thank you very much! :)

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